Q1: week 7- 10/10 – 10/14
Jump to: Tuesday, Wednesday, Thursday, Friday
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10/10 – Monday – Columbus Day – “Indigenous peoples Day”
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10/11 – Tuesday “B” Day – Lab –
Main focus:
Heating and Cooling Curve Review worksheet.pdf
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1. We gather data for the Cooling Curve Lab 4.
Time lapse of the Heating Curve of water below its melting point:
used this to teach with page one of today’s worksheet.
Today’s Lesson:
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10/12 – Wednesday – A Day!
Main focus:
Today’s Demo – Superheating Steam (Water in gas phase).
I burned cotton with water because the gas LOST energy exothermically to the cotton as it condensed back into liquid water. I had to heat the water endothermically to first get the water in the gas phase (boiling). I was able to superheat the water gas (water vapor) because gas has no limit to how hot it can get. There is no other phase for it to change into. I was adding more kinetic energy to the gas THUS I WAS ADDING MORE POTENTIAL ENERGY to the gas!! As the water gas moved faster (as it gained heat from the torch) its potential energy increased! Its potential was so High it had the potential to burn cotton!
H2O (l) + Heat —> H2O(g) Boiling (energy is needed to be absorbed) = endothermic
H2O (g) —> H2O(l) + Heat Condensation (energy released) = exothermic
The heat released exothermically from a gas condensing into a liquid is what burned the cotton balls!
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End Of Tuesday!
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10/13 – Thursday “B” Day – Lab
Ice melting animation:
</div style=”max-width: 560px; margin: auto;”> Notice that the water molecules are initially in the solid phase, which is a 3 dimensional geometric pattern (crystal formation). They are initially vibrating in their fixed positions very slowly (low temperature) and as they absorb kinetic energy (heat) their vibration increases. The vibrations increase up until the molecules start pulling away from each other(melting). Why would the temperature stay constant at this point.
Water Boiling animation:
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End Of Tuesday!
_________________________________________ Jump to: Friday Homework
10/14 – Friday “A” Day

1. melting the white solid: KClO3(s) + heat —> KClO3(l)
2. hot liquid reacts: 2KClO3(l) + heat —> 2 KCl(s) + 3 O2(g)
3. Sucrose (table sugar in gummi bear reacts with oxygen:
C12H22O11 + 35/2 O2 —> 12CO2 + 11H2O + heat (5635 kJ) sucrose

Today’s Lesson: Based on this presentation
Today’s Lesson: Lecture 1.11 – Energy Intro
Today’s Lesson: Demonstrations – part 1
Today’s Lesson: Demonstrations – part 2